NiF2(aq)+Fe2(SO4)3(aq) ==NiSO4 (aq) + FeF3 (s)
balance each of the following chemical equations.
Express your answer as a chemical equation. Identify all of the phases in your answer.
Can help me refresh my memory ...
Of course! I'd be happy to help refresh your memory on balancing chemical equations.
To balance a chemical equation, you need to ensure that the number of atoms on the left side of the equation is equal to the number of atoms on the right side. Here's a step-by-step guide on how to balance the equation you provided:
1. Start by counting the number of atoms for each element on both sides of the equation.
Left side (reactants):
- Nickel (Ni): 1 atom
- Fluorine (F): 2 atoms
- Iron (Fe): 2 atoms
- Sulfur (S): 12 atoms
- Oxygen (O): 12 atoms
Right side (products):
- Nickel (Ni): 1 atom
- Sulfur (S): 4 atoms
- Iron (Fe): 3 atoms
- Fluorine (F): 3 atoms
2. Determine which elements are not balanced. In this case, Nickel, Iron, Sulfur, and Fluorine are not balanced.
3. Start by balancing the elements that appear in the fewest compounds. In this case, let's start with Nickel (Ni).
4. To balance Nickel, add a coefficient of 3 in front of NiSO4 on the right side:
NiF2(aq) + Fe2(SO4)3(aq) → 3NiSO4(aq) + FeF3(s)
5. Now let's balance Iron (Fe). Add a coefficient of 2 in front of FeF3 on the right side:
NiF2(aq) + Fe2(SO4)3(aq) → 3NiSO4(aq) + 2FeF3(s)
6. Lastly, balance Fluorine (F) and Sulfur (S). There are now 6 fluoride ions (F) and 6 sulfate ions (SO4) on the right side, so the equation is already balanced for these elements.
The balanced equation, with the phases indicated, is:
NiF2(aq) + Fe2(SO4)3(aq) → 3NiSO4(aq) + 2FeF3(s)
Note: "(aq)" represents a substance in aqueous solution, and "(s)" represents a solid.
Sure! I can help you refresh your memory on how to balance chemical equations.
To balance a chemical equation, you need to ensure that the number of atoms of each element is the same on both sides of the equation.
Let's balance the given chemical equation step by step:
NiF2(aq) + Fe2(SO4)3(aq) -> NiSO4(aq) + FeF3(s)
First, let's start by balancing the elements other than oxygen and hydrogen. In this case, those elements are nickel (Ni), iron (Fe), sulfur (S), and fluorine (F).
Counting the number of atoms for each element, we have:
Ni: 1 on both sides
Fe: 2 on both sides
S: 4 on the right (SO4) and 1 on the left (NiSO4)
F: 2 on the left (NiF2) and 3 on the right (FeF3)
To balance these elements, we can:
1. Balance nickel (Ni):
We have 1 Ni on each side, so it's already balanced.
2. Balance iron (Fe):
We have 2 Fe on each side, so it's already balanced.
3. Balance sulfur (S):
We have 4 S on the right from the sulfate ion (SO4), and 1 S on the left from the nickel sulfate (NiSO4). To balance the S atoms, we need to put a coefficient of 3 in front of NiSO4:
NiSO4(aq) + 3 Fe2(SO4)3(aq) -> NiSO4(aq) + FeF3(s)
4. Balance fluorine (F):
We have 2 F on the left from the nickel fluoride (NiF2) and 3 F on the right from the iron fluoride (FeF3). To balance the F atoms, we need to put a coefficient of 2 in front of NiF2:
2 NiF2(aq) + 3 Fe2(SO4)3(aq) -> NiSO4(aq) + FeF3(s)
Finally, all the elements are balanced. The balanced chemical equation is:
2 NiF2(aq) + 3 Fe2(SO4)3(aq) -> 2 NiSO4(aq) + FeF3(s)
Don't forget to include the state of matter for each substance. "(aq)" represents an aqueous solution, and "(s)" represents a solid.
I hope this helps refresh your memory on balancing chemical equations! Let me know if you have any other questions.