find the equation of a line that passes through the origin and point (-3,6)
slope=changeinY/changeinX=0-6 /0--3=-6/3
y=mx+b
since 0,0 is a point, b is zero
y=-2x
I don’t understand please
A straight line passes through the origin and the points (-3,6)find the equation of the line.
To find the equation of a line that passes through the origin (0,0) and the point (-3,6), you can use the point-slope form of a linear equation.
The point-slope form of a linear equation is given by:
y - y1 = m(x - x1),
where (x1, y1) is a point on the line, and m is the slope of the line.
In this case, the point on the line is (-3,6), and the origin (0,0) is another point on the line. Let's calculate the slope first using the formula:
slope (m) = (y2 - y1) / (x2 - x1),
where (x1, y1) = (0,0) is the origin, and (x2, y2) = (-3,6) is the other point. Plugging in the values, we get:
m = (6 - 0) / (-3 - 0) = 6 / -3 = -2.
Now that we have the slope, we can substitute the values into the point-slope form and simplify to get the equation of the line:
y - 0 = -2(x - 0).
Simplifying further, we have:
y = -2x.
Therefore, the equation of the line passing through the origin and (-3,6) is y = -2x.