What volume (in Liters) of hydrogen must react to form 17.0L of ammonia according to the following balanced equation:
N2(g) + 3H2(g) --> 2NH3(g)
Assume an excess of N2 and that all are at the same temperature and pressure.
When all are gases, one may use a shortcut.
17.0 L NH3 x (3 moles H2/2 moles NH3) = 17.0 x (3/2) = ??