an iron ore sample was dissolved in Hydrochloric acid the iron was obtained as Fe2+. The solution was titrated with 41.08 mL of a 0.458 M solution of Ce+. Calculate the mass of iron in the original ore sample.
Is that Ce+4?
moles Ce = M x L
moles Fe = moles Ce
mass Fe = moles Fe x molar mass Fe.
To calculate the mass of iron in the original ore sample, we need to understand the stoichiometry of the reaction and perform some calculations based on the given information.
From the given information, we know that the iron in the ore sample is present as Fe2+ ions. The reaction between Fe2+ ions and Ce+ ions can be represented as follows:
2Fe2+ + Ce4+ -> 2Fe3+ + Ce3+
In this reaction, one mole of Ce+ reacts with two moles of Fe2+. Therefore, we can determine the number of moles of Ce+ that reacted with the iron in the solution.
To find the number of moles of Ce+, we can use the equation:
Moles of Ce+ (n) = (Volume of Ce+ solution (V) × Concentration of Ce+ (C)) / 1000
Plugging in the given values, we have:
n = (41.08 mL × 0.458 M) / 1000
Now, since two moles of Fe2+ react with one mole of Ce+, the number of moles of Fe2+ in the solution is half the number of moles of Ce+.
Moles of Fe2+ = n / 2
Once we have the number of moles of Fe2+, we can calculate the mass of iron using its molar mass.
Molar mass of iron (Fe) = 55.845 g/mol
Mass of iron = Moles of Fe2+ × Molar mass of Fe
Now, let's plug in the calculated values:
Mass of iron = (n / 2) × 55.845 g/mol
By substituting the value of n, we can calculate the mass of iron in the original ore sample.