a 1000 kg car engine exerts a force of 3000 N while the car accelerates from 20 m/s to 30 m/s is 5.0 seconds. How much force of resistance does the car experience?
in those five seconds, the avg speed was 25m/s, so the distance covered was 125m
3000*125-forceresitance*125=change in KEnergy.
i don't get that at all...
the change of kinetic energy has to equal the work -frictonenergy that went into it.
To find the force of resistance experienced by the car, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
Let's break down the given information:
- Mass of the car engine (m) = 1000 kg
- Initial velocity (v1) = 20 m/s
- Final velocity (v2) = 30 m/s
- Time taken (t) = 5.0 s
- Force exerted by the car engine (F) = 3000 N
Firstly, we need to calculate the acceleration (a) using the formula:
a = (v2 - v1) / t
Substituting the given values:
a = (30 m/s - 20 m/s) / 5.0 s
a = 10 m/s / 5.0 s
a = 2 m/s²
Now that we have the acceleration, we can calculate the net force acting on the car engine using Newton's second law:
F = m * a
Substituting the values:
F = 1000 kg * 2 m/s²
F = 2000 N
The net force acting on the car engine is 2000 N.
To find the force of resistance experienced by the car, we need to subtract the force exerted by the car engine from the net force:
Force of resistance = Net force - Force exerted by the engine
Force of resistance = 2000 N - 3000 N
Force of resistance = -1000 N
Therefore, the car experiences a force of resistance of -1000 N. The negative sign indicates that the force of resistance is opposing the motion of the car.