A 11.0 box is released on a 37 incline and accelerates down the incline at 0.25 .What is the coefficient of kinetic friction in units uk?
What is the friction force impeding its motion in N?
The force down the plane is
check me
mgSinTheta, the force of friction is mu*mgCosTheta.
Now what is .25? m/s? You have to put units with numbers, 37 (degrees?), .25 ?
Maybe you meant .25m/s^2
net force= ma
mgsintheta-mu*mgCosTheta=m a
check that, and solve for mu.