boy pulls a toy cart of mass 2 kg with a force of 3 N at an angle of 60° with respect to the horizontal road. What is the acceleration produced by the cart?
Well, break the force pulling into a horizontal component, and a vertical component.
Horizontal: 3cos60=1.5N
It bothers me that friction is being ignored, however..
Pullingforce-friction=m*a
1.5-0=2*acceleration solve for acceleration.
To find the acceleration produced by the cart, we can use Newton's second law of motion, which states that the force applied on an object is equal to the mass of the object multiplied by its acceleration.
Given:
Mass of the toy cart (m) = 2 kg
Force applied on the cart (F) = 3 N
Angle of the force with respect to the horizontal road (θ) = 60°
First, we need to resolve the force into its horizontal and vertical components. The horizontal component of the force (Fh) can be found using trigonometry:
Fh = F * cos(θ)
= 3 N * cos(60°)
= 3 N * 0.5
= 1.5 N
Next, we can calculate the acceleration produced by the cart using Newton's second law:
F = m * a
1.5 N = 2 kg * a
Dividing both sides by 2 kg, we find:
a = 1.5 N / 2 kg
a = 0.75 m/s^2
Therefore, the acceleration produced by the cart is 0.75 m/s^2.