Two sides of a triangle are equal in length. The length of the third side is three meters less that the sum of the lengthsof the other two sides.Find the length of the longest side of the triangle if its perimeter is 29 meters.
Please help.
Thanks.
Let each of the two equal sides be x m
"he length of the third side is three meters less that the sum of the lengthsof the other two sides"
translate that into math, does it not become 2x - 3 ??
Perimeter means the sum of all 3 sides, so
x + x + 2x-3 = 29
Solve and let me know what you got,
see if your answer satisfies the conditions stated in your problem
4x=32 so x =8.
Thanks,
Lucy
To solve this problem, we can use the information given and set up an equation.
Let's assume the length of the equal sides is x, and the length of the third side is y.
We are given that the third side is three meters less than the sum of the lengths of the other two sides. So, we can write the equation:
y = x + x - 3
We are also given that the perimeter of the triangle is 29 meters. The perimeter of a triangle is the sum of all its sides. In this case, it would be:
x + x + y = 29
Now, we need to substitute the value of y from the first equation into the second equation:
x + x + (x + x - 3) = 29
Simplifying this equation:
4x - 3 = 29
Adding 3 to both sides of the equation:
4x = 32
Dividing both sides by 4:
x = 8
Now, we have found the value of x, which represents the length of the equal sides. To find the length of the longest side, we need to substitute this value back into the first equation:
y = x + x - 3
y = 8 + 8 - 3
y = 16 - 3
y = 13
Therefore, the length of the longest side of the triangle is 13 meters.