How much heat is absorbed by a 25.0-g sample of gold at 25.0 degrees celcius when it is immersed in boiling water?
q = mass Au x specific heat Au x (Tfinal-Tinitial)
Tfinal = 100
Tinitial = 25
To find the amount of heat absorbed by a sample of gold, you can use the equation:
q = m × c × ΔT
Where:
q is the heat absorbed or released by the substance
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature
First, let's find the specific heat capacity of gold. The specific heat capacity of gold is approximately 0.13 J/g°C.
Next, calculate the change in temperature (ΔT). The initial temperature of the gold is 25.0 degrees Celsius, and it is immersed in boiling water, which is approximately 100 degrees Celsius. Therefore, ΔT = (final temperature) - (initial temperature) = 100°C - 25.0°C = 75.0°C.
Now you have all the information to calculate the heat absorbed (q). Plug in the values into the equation:
q = 25.0 g × 0.13 J/g°C × 75.0°C
q = 325.0 J
Therefore, the 25.0-g sample of gold absorbs 325.0 joules of heat when immersed in boiling water.