a skydiver who weighs 500N reaches terminal velocity of 90 km/h. the air resistence on the diver is then...
a)90N
b)250N
c)410N
d)500N
e)none of these
EXPLAIN PLEASE :)
500N
To calculate the air resistance on the skydiver, we need to use the formula for air resistance, which is given by:
F = 0.5 * ρ * A * Cd * v^2
Where:
F is the force of air resistance,
ρ is the density of air,
A is the cross-sectional area of the diver,
Cd is the drag coefficient of the diver, and
v is the velocity of the diver.
Since we are not given the values for density, cross-sectional area, and drag coefficient, we cannot calculate the air resistance accurately. However, we can roughly estimate it.
Terminal velocity is the maximum velocity reached by an object falling through the air. At terminal velocity, the force of gravity pulling the skydiver downwards is equal to the force of air resistance pushing against the skydiver.
Hence, at terminal velocity, the weight of the skydiver is balanced by the air resistance. In this case, since the skydiver weighs 500N, the air resistance should also be around 500N.
Therefore, the correct answer would be option d) 500N.
To determine the air resistance on the skydiver, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration. In this case, the net force acting on the skydiver is the difference between the gravitational force (weight) and the air resistance.
Given that the weight of the skydiver is 500N, we know that the gravitational force acting on the skydiver is 500N. At terminal velocity, the skydiver experiences zero acceleration, meaning the net force acting on the skydiver is also zero.
To find the air resistance, we need to subtract the weight (gravitational force) from the net force. If the net force is zero, then the air resistance must also be equal to the weight of the skydiver.
Therefore, the air resistance on the skydiver is 500N. So, the correct answer is (d) 500N.
Terninal velocity is reached when the weight equals the air resistance force. At that point, forces are in balance and acceleration stops.
That should be a good clue.