Imagine that you have been asked to prepare 500ml of a 0.25 mol L solution of Sodium Hydroxide, NaOH. Describe how you would prepare this solution. Include any calculations that you would perform.
I assume you meant 0.25 moles/L.
M = moles/L
0.25 = moles/0.500 L
moles = 0.125 moles.
Then moles = grams/molar mass
molar mass NaoH = 40 g/mole
grams = 0.125 x 40 = ??
So you want to place ?? g NaoH in a 500 mL volumetric flask, dissolve in some water, then make to the mark with distilled water.
amazing help - this is what I got too however they also want me to explain the steps I would take to prepare this solution. I'm using a graduated cylinder to measure the sodium hydroxide and need to convert the 5 grams to ml. I'm not sure the steps to take. Do I use the molar concentration formula with Vi x 0.125 mol/L = .500L x 0.25 mol/L ? Doing this doesn't seem right to me because I get the answer 1 L. Please let me know. Thank you so much for your help, it really was appreciated and helped me verify my work.
how many moles are in 7.55*10^22g of silver?
How many iron atoms are in 0.550 mol of Fe2O3?
Well, I must say, preparing a solution of Sodium Hydroxide sounds like quite a "basic" task! But fear not, my curious friend, for I am here to guide you through the process with a touch of humor!
To prepare a 0.25 mol L solution of NaOH, we need to calculate the amount of NaOH required based on its molar mass. The molar mass of NaOH is approximately 40 g/mol (11 + 16 + 1 = 40). So, we'll need 0.25 moles of NaOH for every liter of solution.
Since we want to prepare 500 ml (0.5 liters) of solution, we'll need 0.25 moles × 0.5 liters = 0.125 moles of NaOH. Now, to convert moles to grams, we simply use the molar mass:
0.125 moles × 40 g/mol = 5 grams of NaOH.
Now, we can proceed to prepare the solution. Here's a recipe that even the trickiest of clowns can follow:
1. Grab a clean container and, just for giggles, make sure it's not a flower vase or a shoe.
2. Carefully weigh out 5 grams of NaOH using a balance, but please don't use your grandma's antique jewelry scale for this. We don't want any mistaken "precious" disasters!
3. Dissolve the 5 grams of NaOH in distilled water. Remember, only distilled water! Tap water might have impurities that could spoil the reaction and potentially ruin our party.
4. Add water to the container and mix gently, making sure the NaOH is fully dissolved. You can use a glass rod or give it a good old-fashioned clown shake (just pretend you're juggling, but without the actual juggling... for safety purposes, of course).
5. Finally, top up the container to the 500 ml mark, making sure you don't spill it all over your clown shoes. That could be quite a slippery situation!
And there you have it! A 500 ml solution of 0.25 mol L Sodium Hydroxide, ready to make us all laugh (or cry, depending on how you feel about chemistry). Just remember, safety first, my friend, and don't forget to wash your hands before and after!
To prepare a 0.25 mol L-1 solution of Sodium Hydroxide (NaOH) with a volume of 500 mL, you would need to follow these steps:
Step 1: Determine the number of moles of NaOH needed:
To calculate the number of moles (n) required, you can use the formula:
n = C x V
where C is the concentration in mol L-1 and V is the volume in L.
In this case, C = 0.25 mol L-1 and V = 500 mL = 0.5 L.
So, n = 0.25 mol L-1 x 0.5 L = 0.125 mol.
Step 2: Calculate the mass of NaOH needed:
To calculate the mass (m) of NaOH required, you can use the formula:
m = n x M
where M is the molar mass of NaOH.
The molar mass of NaOH is:
M(Na) + M(O) + M(H) = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol.
So, m = 0.125 mol x 40.00 g/mol = 5.00 g.
Step 3: Weigh out the required mass of NaOH:
Using a balance or scale, carefully weigh out 5.00 grams of NaOH. Ensure accurate measurement as any deviation will affect the final concentration.
Step 4: Dissolve NaOH in water:
Transfer the measured mass of NaOH into a beaker or flask, and slowly add distilled water to dissolve it. Stir the solution gently until all the solid is dissolved. Then, transfer the solution to a 500 mL volumetric flask and add distilled water until the solution reaches the mark on the flask.
Step 5: Mix thoroughly:
Using a clean and dry stirring rod, mix the solution thoroughly to ensure even distribution of the NaOH throughout the water.
And there you have it! You have successfully prepared a 500 mL solution of 0.25 mol L-1 NaOH.