neglecting wind restitance,the height,h,in feet,of a sky diver,t,seconds after she jumps from an airplane 1,648 above the ground is given by the formula h=-16ft square +1648.if the parachute opens 4.5 secinds after the sky diver leaveshe airplane,about how far will she be from the ground when the parchute opens? will it be -16 x 4.5 square + 1648=1324?if not may you show me the correct answer and solve please.
A private airplane leaves an airport and flies due east at 192 km/hr. Two hours later, a jet leaves the same airport and flies due east at 960 km/hr. How long after the jet leaves will it overtake the plane?
784
To find the height of the skydiver when the parachute opens, we need to substitute the time value into the given formula.
The formula provided is:
h = -16t^2 + 1648
Given that the parachute opens after 4.5 seconds, we substitute t = 4.5 into the formula:
h = -16(4.5)^2 + 1648
Now we'll solve this equation step-by-step:
h = -16(20.25) + 1648
h = -324 + 1648
h = 1324
So, the height of the skydiver when the parachute opens is 1324 feet, as you correctly calculated. Therefore, she will be approximately 1324 feet from the ground when the parachute opens.