if 22.5 mL of 0.383 M HCl are required to completely neutralize 20.0 mL of KOH, what is the molarity of the KOH solution?
The answer is 0.431M
Well, let's have a little chemistry circus, shall we? The merry bottle of HCl moseyed on over and ran into the party-loving KOH. They quickly got into a multidimensional dance-off, and you could tell it was a titration tango! The HCl, the wild one that it is, took 22.5 mL to bring the KOH to its knees.
Now, let's figure out the molarity of this KOH solution. The number of moles of HCl used can be calculated by multiplying the volume (in liters) by the molarity, which gives us:
moles of HCl = volume of HCl (in L) * molarity of HCl
We know the molarity of HCl (0.383 M) and the volume of HCl used (22.5 mL), so let's convert that to liters:
22.5 mL = 22.5 / 1000 L
Now, we can calculate the moles of HCl:
moles of HCl = (22.5 / 1000) L * 0.383 M
Since the reaction between HCl and KOH is 1:1, this means the number of moles of KOH is also the same as the moles of HCl. And the volume of KOH used is 20.0 mL, which is also 20.0 / 1000 L. So now we can find the molarity of KOH:
molarity of KOH = moles of KOH / volume of KOH (in L)
So to sum it all up, the molarity of the KOH solution is:
molarity of KOH = (22.5 / 1000) L * 0.383 M / (20.0 / 1000) L
Do the math, and you'll get the answer you're looking for! Just be careful not to juggle with those formulas too much, or you might end up with a chemistry circus that's more chaotic than entertaining!
To determine the molarity of the KOH solution, you can use the concept of stoichiometry. The balanced chemical equation for the reaction between HCl and KOH is:
HCl + KOH -> H2O + KCl
From the equation, we can see that the ratio of moles of HCl to KOH is 1:1.
First, we need to calculate the number of moles of HCl using the given volume and molarity. The formula to calculate moles is:
Moles = Molarity x Volume
Where,
Moles = Number of moles
Molarity = Molar concentration (in mol/L)
Volume = Volume (in L)
Given: Molarity of HCl solution (M1) = 0.383 M
Volume of HCl solution (V1) = 22.5 mL = 22.5/1000 L = 0.0225 L
Using the formula, calculate the number of moles of HCl:
Moles of HCl = 0.383 M x 0.0225 L = 0.0086325 moles
Since the stoichiometry of the balanced equation is 1:1, the number of moles of KOH in the reaction would also be 0.0086325 moles.
Now, calculate the molarity of KOH by using the equation:
Molarity = Moles / Volume
Where,
Molarity = Molar concentration (in mol/L)
Moles = Number of moles
Volume = Volume (in L)
Given: Volume of KOH solution (V2) = 20.0 mL = 20.0/1000 L = 0.02 L
Using the formula, calculate the molarity of KOH:
Molarity of KOH = 0.0086325 moles / 0.02 L = 0.431625 mol/L
Therefore, the molarity of the KOH solution is 0.431625 mol/L.
http://www.jiskha.com/display.cgi?id=1286983526
The neutrality equation is the neutrality equation, it does not change.
reread that post.