1. A man pulls a 300 N object across a horizontal surface using a 100 N force applied at a 35° angle. What is the normal force? If the object is pulled at constant speed, what is the coefficient of friction?
normal force would be N=mg f+sin
You really need to get the book I suggested.
No, normal force is weight (mg) minius the upward lifting force from the rope 100sintheta
ok i wont have time this is due at 1
To find the normal force in this scenario, we can use the equation N = mg + f * sin θ, where N is the normal force, m is the mass of the object, g is the acceleration due to gravity, f is the force applied, and θ is the angle between the applied force and the horizontal surface.
However, in the given problem, we are not provided with the mass of the object, so we cannot directly calculate the normal force. Instead, we need to use the fact that the object is pulled at a constant speed to determine the coefficient of friction.
When an object is moving at a constant speed, the net force acting on it is zero. In this case, the applied force (100 N) must be balanced by the force of friction. The force of friction can be calculated using the equation f friction = μ * N, where μ is the coefficient of friction.
Since the net force is zero, the force of friction must be equal in magnitude and opposite in direction to the applied force. Hence, we can write f friction = 100 N.
Substituting the equation for the frictional force, we get μ * N = 100 N.
Here, we can see that the normal force (N) cancels out, so the coefficient of friction is independent of the normal force and can be determined solely by the given information. Therefore, the coefficient of friction is μ = 100 N / N.
To determine the coefficient of friction accurately, we need more information about the problem, such as the mass of the object. Without that information, we can't calculate the coefficient of friction precisely.