3. A 5 N block slides down a 20° incline at constant speed. What is the frictional force?

The force moving it down is gravity. So at constant speed, fricion must equal gravity.

Forcegravity=mg*SinTheta

ok so i put 5(9.8)sin(20) but i get 44.73 which i think i typed it in wrong

To find the frictional force acting on the block, we first need to understand the forces acting on it. In this scenario, we have two primary forces: the gravitational force acting vertically downwards and the frictional force acting parallel to the incline.

To determine the frictional force, we can use the fact that the block is sliding down the incline at a constant speed. This implies that the net force acting on the block is zero. At constant speed, the force of gravity pulling the block downwards is balanced by the frictional force pushing back up the incline.

The gravitational force acting on the block can be determined using the formula:

Gravitational Force = mass × acceleration due to gravity

Since the mass is not provided in the question, we cannot directly calculate the gravitational force. However, we know that the weight of an object can be determined using the formula:

Weight = mass × acceleration due to gravity

In this case, the weight is given as 5 N (Newton), which is the force applied by gravity. Therefore, if we divide this weight by the acceleration due to gravity (approximately 9.8 m/s^2), we can find the mass of the block.

Mass = Weight / Acceleration due to gravity

Mass = 5 N / 9.8 m/s^2

After calculating the mass, we can find the gravitational force acting on the block.

Next, the incline angle of 20° is given. We can determine the component of the gravitational force acting parallel to the incline by multiplying the gravitational force by the sine of the angle (in this case, 20°).

Force parallel to the incline = Gravitational Force × sine(angle)

Finally, since the block is moving at constant speed, the frictional force must be equal in magnitude but opposite in direction to the force parallel to the incline. Therefore, the frictional force is:

Frictional force = Force parallel to the incline

By substituting the calculated values, you can find the frictional force acting on the block.