please I really need help with these
1. A man pulls a 300 N object across a horizontal surface using a 100 N force applied at a 35° angle. What is the normal force? If the object is pulled at constant speed, what is the coefficient of friction?
To find the normal force, we need to first understand the forces acting on the object. In this case, we have the force applied, which is 100 N at an angle of 35°, and the weight of the object, which we can assume is 300 N.
The normal force is the force exerted by the surface to support the weight of the object and balance the vertical forces. Since the object is on a horizontal surface, the normal force acts in the upward direction and has the same magnitude as the weight.
So, the normal force is 300 N.
To find the coefficient of friction, we need to use the equation for friction force:
friction force = coefficient of friction * normal force
Since the object is pulled at a constant speed, the force of friction must be equal to the pulling force (100 N) to maintain that constant speed.
So, we can set up the equation:
100 N = coefficient of friction * 300 N
By rearranging the equation, we can solve for the coefficient of friction:
coefficient of friction = 100 N / 300 N
coefficient of friction = 1/3
Therefore, the coefficient of friction is 1/3 or approximately 0.33.