The latent heat of vaporization of water is 540 calories/gram. How many calories are required to completely vaporize 500 grams of water?

it is 270000

Given,

heat of vaporization of water is 540 cal per gram
therefore amount of heat required
( 500 × 540) cal
is equal to 270000 calories...

Oh, so you just set it up like a proportion?

And thank you. (:

wah

It is not called a PROPORTION

It is called a MULTIPLICATION

To calculate the amount of calories required to completely vaporize 500 grams of water, you can use the formula:

Energy = Mass * Latent Heat of Vaporization

Substituting the given values into the formula:

Energy = 500 grams * 540 calories/gram
= 270,000 calories

Therefore, 270,000 calories are required to completely vaporize 500 grams of water.

1 g = 540 calories

500 g = ? calories

Since the mass is 500 times 1 g, so the number of calories
= 500*540 calories