According to your calculations a reaction should yield 5.67 g of oxygen O2. What do you expect the volume to be at 23 degrees C and 0.985 atm?

I got the all the amounts

5.67 g
23 degrees C = 296 K
.985 atm

And use the ideal gas law

Can you help me out by starting it
again

Same as last question. No need for me to type all that again.

mols = grams/molar mass = 5.67/32
Don't forget to change T to Kelvin.

yes.

Sure! To find the volume of oxygen gas produced in this reaction, we can use the ideal gas law, which states:

PV = nRT,

where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.

To begin, we need to calculate the number of moles of oxygen gas produced. We can do this by first converting the mass of oxygen to moles using its molar mass. The molar mass of oxygen is approximately 32 g/mol.

Given:
Mass of oxygen (O2) = 5.67 g
Molar mass of oxygen (O2) = 32 g/mol

First, calculate the number of moles of oxygen:
moles = mass / molar mass
moles = 5.67 g / 32 g/mol

Now that we have the number of moles of oxygen (O2), we can proceed to apply the ideal gas law equation. We have already been given the temperature in Celsius (23°C), so the first step is to convert it to Kelvin.

T(K) = T(°C) + 273.15
T(K) = 23°C + 273.15
T(K) = 296.15 K

Given:
Pressure (P) = 0.985 atm
Temperature (T) = 296.15 K
Number of moles (n) = calculated above

Now we can use the ideal gas law equation to calculate the volume:

PV = nRT

V = nRT / P

Substituting the given values:

V = (moles) * (R) * (T) / P

At this point, we need to know the value of the ideal gas constant (R). The ideal gas constant is typically given as 0.0821 L·atm/(mol·K).

Given:
Ideal gas constant (R) = 0.0821 L·atm/(mol·K)

Now we can proceed with the calculations:

V = (moles) * (R) * (T) / P
V = (5.67 g / 32 g/mol) * (0.0821 L·atm/(mol·K)) * (296.15 K) / 0.985 atm

By substituting and evaluating the equation, you will find the expected volume of oxygen gas produced in liters.

.985(V)=.177(.0821)(296)=

Same thing do you multiply and then divide by .985