DNA is approximately 2.5 nm in length. If an average man is 6 feet tall, how many DNA molecules could be stacked end to end in an average man?
Convert 6 feet to nm. I have 1.828 x 10^9 nm but you need to confirm that.
1.828 x 10^9/2.5 = # DNA molecules end to end.
To calculate the number of DNA molecules that could be stacked end to end in an average man, we need to convert the height of the man from feet to nanometers and then divide it by the length of a DNA molecule.
1 foot is approximately 30.48 centimeters, and 1 centimeter is equal to 10 million nanometers. Therefore, 1 foot is equal to 30.48 * 10^7 nanometers.
An average man is 6 feet tall, so his height in nanometers would be:
6 feet * 30.48 * 10^7 nanometers/foot = 182.88 * 10^7 nanometers.
Now, let's calculate the number of DNA molecules that can be stacked end to end in this height:
Number of DNA molecules = (Height of man) / (Length of DNA molecule)
= (182.88 * 10^7 nanometers) / (2.5 nanometers)
Dividing the two values, we get:
Number of DNA molecules = 73.152 * 10^7 molecules
Therefore, approximately 73.152 * 10^7 DNA molecules could be stacked end to end in an average man.
To calculate the number of DNA molecules that could be stacked end to end in an average man, we need to convert the length of DNA and the height of the man into the same unit of measurement.
First, let's convert the height of the man from feet to nanometers (nm):
1 foot = 0.3048 meters
1 meter = 1,000,000,000 nm
So, 6 feet = 6 * 0.3048 * 1,000,000,000 nm = 1,829,440,000 nm
Now, let's calculate the number of DNA molecules that can fit in this height:
Length of DNA = 2.5 nm
Number of DNA molecules = Total height / Length of DNA
Number of DNA molecules = 1,829,440,000 nm / 2.5 nm
Number of DNA molecules = 731,776,000
Therefore, approximately 731,776,000 DNA molecules could be stacked end to end in an average man who is 6 feet tall.