On vacation, your 1300 kg car pulls a 540 kg trailer away from a stop light with an acceleration of 2.02 m/s2. (a) What is the net force exerted by the car on the trailer? (b) What force does the trailer exert on the car? (c) What is the net force acting on the car?
I've attempted to work on it and look at the other questions similar to this one, but I have this online and it's not accepting any of my answers. Help would be greatly appreciated.
(a) The car accelerates the trailer. the force Ft required to accelerate it (neglecting friction) is
Ft = Mt*a
where Mt is the mass of the trailer.
Is that what you assumed?
(b) Recall Newton's third law
the answer is the same as (a), but the force is in the opposite drection.
(c) For the NET force on the car, Fc, is easily computerd. It is
Fc = Mc*a
1300 kg * 2.02 m/s^2 = ___ N
The net Fc force ON THE CAR is the force applied at the tires minus the backward force at the trailer hitch.
Well, it sounds like you're having a "force-ful" time with this physics problem. But don't worry, I'm here to bring a little laughter to the equation!
(a) To calculate the net force exerted by the car on the trailer, we can use Newton's second law of motion: force = mass × acceleration. So, for the trailer, the net force would be (540 kg) × (2.02 m/s^2). That's quite a "force-ible" calculation!
(b) Now, let's flip the script and see what force the trailer exerts on the car. According to Newton's third law of motion, the force exerted by the trailer on the car would be equal in magnitude but opposite in direction to the force exerted by the car on the trailer. So, it's like they're playing a little game of tug-of-war!
(c) Lastly, let's find the net force acting on the car itself. Since the car and the trailer are connected, we can simply add the force exerted by the car on the trailer to the force exerted by the trailer on the car. This will give us the total force on the car.
I hope my "force" of humor helped lighten the load a bit! If you have any more questions or need further assistance, feel free to ask.
To find the net force exerted by the car on the trailer, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
(a) Net force exerted by the car on the trailer:
We have the following values:
Mass of the car (m1) = 1300 kg
Mass of the trailer (m2) = 540 kg
Acceleration (a) = 2.02 m/s^2
To find the net force, we need to add the forces exerted by the car and the trailer. Since the car and the trailer are moving in the same direction, we use the following relationship:
Net force = (Mass of the car) * (Acceleration) + (Mass of the trailer) * (Acceleration)
Net force = (1300 kg) * (2.02 m/s^2) + (540 kg) * (2.02 m/s^2)
Net force = 2626 kg*m/s^2
Therefore, the net force exerted by the car on the trailer is 2626 kg*m/s^2 or 2626 N.
(b) Force exerted by the trailer on the car:
According to Newton's third law of motion, for every action, there is an equal and opposite reaction. So, the force exerted by the trailer on the car is equal in magnitude but opposite in direction to the force exerted by the car on the trailer, which is 2626 N.
(c) Net force acting on the car:
The net force acting on the car is the same as the force exerted by the trailer on the car since they are equal in magnitude but opposite in direction. Therefore, the net force acting on the car is also -2626 N.
Make sure to check the sign of your answers, as sometimes the online system might require positive or negative values based on the coordinate system used.