I have to make it so the results

of the average is less than 25.
Average of three volumes:

13+11.3+9.2= 33.5/ 3= 11.16 mL

Convert mL to L

11.16 mL x 10^-3 L = .01116 L

The number of moles of HCl was calculated using the stoichiometry :

1 mole HCl= ½ moles CO3

.01116 L x 1.0 mol = .01116 mol HCl
---------
1 L

The number of moles of CO3 was calculated:

.01116/ 2 = .00558 mol CO3

The molar mass of CO3 was determined by using the equation (mass of unknown/mole CO3):

0.75 g unknown/ .00558 mol CO3= 134.40 g/mol CO3

The Molarities of CO3 was determined by:

CO3= 12+16+16+16=60 g

134.40 g/mol – 60 g =74.4 mol/2 =37.2 g/ mol

I have to make it so the results

of the average is less than 25.
Average of three volumes:

13+11.3+9.2= 33.5/ 3= 11.16 mL
I think the average is 11.166666 which rounds to 11.17 (and you will need to change it for the next problem.

Convert mL to L

11.16 mL x 10^-3 L = .01116 L

OK but with the new number. Also, I would show 10^-3 L/mL so the problem would look this way.
11.17 mL x 10^-3 L/mL =


I don't understand the remainder of the question.

To determine the molarities of CO3, you first need to calculate the number of moles of CO3 present. From the given information, we know that the number of moles of CO3 is 0.00558 mol.

The molar mass of CO3 is given as 134.40 g/mol. To calculate the mass of the unknown substance, we can use the equation:

mass of unknown = mole ratio * mass of CO3

From the equation, we can see that the mole ratio of CO3 to the unknown substance is 0.75 g unknown / 0.00558 mol CO3.

Plugging in the values, we get:

mass of unknown = 0.75 g unknown / 0.00558 mol CO3 = 134.40 g/mol CO3

Now, to find the molarities of CO3, we need to subtract the molar mass of CO3 (given as 60 g) from the mass of the unknown substance:

74.40 g/mol CO3 - 60 g = 14.4 g/mol

Finally, to calculate the molarities of CO3, divide the mass of CO3 (37.2 g/mol) by the number of moles of CO3 (0.00558 mol):

molarity of CO3 = 37.2 g/mol / 0.00558 mol = 6675.27 mol/L

Therefore, the molarities of CO3 is approximately 6675.27 mol/L.