When 0.042 moles of aluminum sulfate are

dissolved in enough water to make 763
milliliters of solution, what is the molarity of sulfate ions?
Answer in units of M.

I wonder what is going on here? this is incredibly easy

Moles sulfate ions in Al2(SO4)3
Molarity= molessulfateions/liters of solution
= 3*.042/.763 moles/liter

12.4

To find the molarity of sulfate ions, we need to calculate the number of moles of sulfate ions present in the solution.

Aluminum sulfate (Al2(SO4)3) dissociates in water to form three sulfate ions (SO4^-2) per formula unit.

First, let's calculate the moles of aluminum sulfate:

Moles of aluminum sulfate = mass / molar mass

The molar mass of aluminum sulfate (Al2(SO4)3) can be calculated as follows:

Molar mass of Al = 26.98 g/mol
Molar mass of S = 32.07 g/mol
Molar mass of O = 16.00 g/mol

Molar mass of aluminum sulfate (Al2(SO4)3) = (2 × 26.98) + (3 × 32.07) + (12 × 16.00) = 342.15 g/mol

Now, let's calculate the moles of aluminum sulfate:

Moles of aluminum sulfate = 0.042 moles

Now, we need to calculate the moles of sulfate ions:

Moles of sulfate ions = moles of aluminum sulfate × (3 moles of sulfate ions / 1 moles of aluminum sulfate)

Moles of sulfate ions = 0.042 moles × (3 moles / 1 mole) = 0.126 moles

Finally, we need to calculate the molarity of sulfate ions:

Molarity (M) = moles of solute / volume of solution (in liters)

Volume of solution = 763 milliliters = 763/1000 L = 0.763 L

Molarity of sulfate ions = 0.126 moles / 0.763 L = 0.165 M

Therefore, the molarity of sulfate ions is 0.165 M.

To find the molarity of sulfate ions, we need to know the number of moles of sulfate ions present in the solution.

Given that 0.042 moles of aluminum sulfate are dissolved, we can determine the number of moles of sulfate ions by multiplying the number of moles of aluminum sulfate by the ratio of sulfate ions to aluminum sulfate in the compound.

The chemical formula for aluminum sulfate is Al2(SO4)3, which indicates that there are 3 sulfate ions for every 1 aluminum sulfate molecule.

Therefore, the number of moles of sulfate ions can be calculated as follows:

Number of moles of sulfate ions = (Number of moles of aluminum sulfate) * (3 sulfate ions / 1 aluminum sulfate)

Number of moles of sulfate ions = 0.042 moles * (3 mol / 1 mol)

Number of moles of sulfate ions = 0.126 moles

Next, we need to calculate the molarity of sulfate ions. Molarity is defined as the number of moles of solute per liter of solution.

We are given that the solution is made to a final volume of 763 milliliters, which is equivalent to 0.763 liters.

Molarity of sulfate ions = (Number of moles of sulfate ions) / (Volume of solution in liters)

Molarity of sulfate ions = 0.126 moles / 0.763 liters

Molarity of sulfate ions ≈ 0.165 M (rounded to three decimal places)

Therefore, the molarity of sulfate ions in the solution is approximately 0.165 M.