Please help
How do you graph the radical that is below
negative of the sqrt(x+1)
my teacher said we should set up x and y according to parent function. The endpoint of this would be (-1,0)
How do I find the other points-I'm really stuck
x y(-sqrt(x+1)
Now make a table of values:
0; -1
-1; 0
1; -1.41
5; -sqrt6
make a few more points (just choose random values of x, figure y).
Thank you
To graph the radical function -√(x+1), you can start by setting up a table of values to find the corresponding points on the graph. Since your teacher mentioned setting up x and y according to the parent function, we can assume that the parent function is the basic square root function y = √x.
Let's start with the endpoint you mentioned: (-1, 0). By substituting x = -1 into the function, you can find the corresponding y-value:
y = -√(-1+1)
y = -√0
y = 0
So, (-1, 0) is indeed a point on the graph.
To find other points, you can choose different values of x and substitute them into the function to get the corresponding y-values. Let's choose a few values for x and calculate the corresponding y-values:
1. When x = -2:
y = -√(-2+1)
y = -√(-1)
y = -(√(-1))
The square root of a negative number is not a real number, so there is no y-value for this x-value.
2. When x = 0:
y = -√(0+1)
y = -√1
y = -1
3. When x = 1:
y = -√(1+1)
y = -√2
You can continue to choose more values for x and calculate their corresponding y-values. Once you have enough points, plot them on a coordinate plane and connect them with a curve. Don't forget to label the points on the graph to make it easier to interpret.
Remember, whenever you graph a function, it's always recommended to choose x-values that are evenly spaced to get a clear picture of the overall shape of the graph.