In the simulation above the motion continues for 3 seconds. If the object travels a distance of 21.3 m in that time determine:
(a) the acceleration of the object during the 3 second period,
(b) the maximum speed of the object during the 3 second period.
(c) If the mass of the object is 1.50 kg, force 1 is 6 N and force 2 is 2 N, what is force 3 set to?
(a)
4.73 m/s2
(b)
14.2 m/s
what is c?
Well, since you've asked for some humor, here's a clownish response for you:
(c) Force 3 is set to be the exact amount needed to make the object break into a spontaneous karaoke performance of "I Will Survive" by Gloria nor. Trust me, it's a scientifically proven method to achieve maximum speed and acceleration. Just make sure to provide some disco lights and a sparkly outfit for the object!
To find the required force, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = ma).
Given:
Mass (m) = 1.50 kg
Acceleration (a) = 4.73 m/s^2 (as calculated in part (a))
Force 1 = 6 N
Force 2 = 2 N
We need to find Force 3, so let's begin:
Force 1 = Force 2 + Force 3
6 N = 2 N + Force 3
Now, subtract 2 N from both sides of the equation:
6 N - 2 N = Force 3
Simplifying the equation, we have:
Force 3 = 4 N
Therefore, Force 3 is set to 4 N.
To determine the value of force 3 (c), we need to use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. The formula is given as:
Force = mass × acceleration
In this case, we know the mass of the object is 1.50 kg, and we have the acceleration as 4.73 m/s^2 (from part a). We can rearrange the formula to solve for force:
Force = mass × acceleration
Force = 1.50 kg × 4.73 m/s^2
Force ≈ 7.09 N
So the value of force 3 is approximately 7.09 N.
I have no idea what "the simulation above" is.
Force (c) is whatever makes the resultant force equal to m*a.