The force on a wire is a maximum of 7.33E-2 N when placed between the pole faces of a magnet. The current flows horizontally to the right and the magnetic field is vertical. The wire is observed to "jump" toward the observer when the current is turned on. If the pole faces have a diameter of 12.9 cm, estimate the current in the wire if the field is 0.111 T.


If the wire is tipped so that it makes an angle of 10.6° with the horizontal, what force will it now feel?

F(new)=F(old)x Cos(angle)

To estimate the current in the wire, we can use the formula for the force on a wire in a magnetic field:

F = BIL sin(θ)

Where:
F is the force on the wire
B is the magnetic field strength
I is the current in the wire
L is the length of the wire
θ is the angle between the wire and the magnetic field

In the given problem, the force on the wire is a maximum of 7.33E-2 N when the current is turned on, the magnetic field is 0.111 T, and we need to find the current in the wire.

Since we are given the force, we can rearrange the formula to solve for I:

I = F / (B * L * sin(θ))

The diameter of the pole faces is given as 12.9 cm, which means the length of the wire (L) is equal to the diameter.

L = 12.9 cm = 0.129 m

The angle between the wire and the magnetic field is given as 10.6°.

Plugging in the given values into the formula:

I = 7.33E-2 N / (0.111 T * 0.129 m * sin(10.6°))

Calculating the expression, we can find the estimated current in the wire.