HNO3+NaOH --- H2O+NaNO3 What is formed in the solution besides Cu(OH)2?
To determine what is formed in the solution besides Cu(OH)2, we need to look at the reaction between HNO3 (nitric acid) and NaOH (sodium hydroxide), which produces water (H2O) and sodium nitrate (NaNO3).
HNO3 is a strong acid, and NaOH is a strong base. When an acid reacts with a base, it typically results in a neutralization reaction. In this case, the hydrogen ion (H+) from the acid combines with the hydroxide ion (OH-) from the base to form water. The remaining ions from the acid and the base combine to form a salt.
In the given reaction, the hydrogen ion (H+) from HNO3 combines with the hydroxide ion (OH-) from NaOH, resulting in water (H2O). The remaining ions, sodium (Na+) and nitrate (NO3-), combine to form sodium nitrate (NaNO3).
Therefore, the compound formed in the solution besides Cu(OH)2 is sodium nitrate (NaNO3).