# physics

A sports car of mass 950 kg (including the driver) crosses the rounded top of a hill (r = 88 m) at 27 m/s.

Determine the normal force exerted by the road on the car. Determine the normal force exerted by the car on the 72-kg driver.

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1. force =mg-mv^2/r where m is 72kg.

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bobpursley
2. Is the equation above used to determine the normal force exerted by the road on the car?

When I used the equation I got (72)(9.8) - (72)(729)/88 = 1.2 (2 sig figs)

This answer was incorrect. What am I doing wrong.

And.... what equation can I use to figure out the 2nd part?

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3. if you haven't already figured it out the equation is for both the driver and car,

a)you pluged in for driver but it should be weight of the car so its
=(950 * 9.8)-(950*729/88)
=(72)(9.8) - (72)(729)/8
C) to determine the speed of the car with no normal force exerted on the driver you simply V= sqrt(91*9.8)

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4. sorry i made some typing errors
B)=(72 * 9.8) - (72*729/88)
which i got 109 and that = 1.1 *10^2
C)v= sqrt(88*9.8)
the 91 was from my problem i had to do.
hope this helps

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5. B=72-9-8

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