A 9500kg car traveling at 16m/s strikes a second car. The two stick together and move off with a speed of 6.0m/s. What is the mass of the second car?
15833kg
(m1v1)+9m2v2)=v (m1+m2)
(m1v1)+(m2v2)=v (m1+m2)
v2 cancles put so now use
M1V2= V (M1+M2)
To find the mass of the second car, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
Momentum is defined as the product of mass and velocity. Therefore, the momentum before the collision is given by:
Momentum before collision = (mass of the first car) × (velocity of the first car) = (9500 kg) × (16 m/s)
After the collision, the two cars stick together and move off with a common velocity. We are given that the final velocity is 6.0 m/s.
Momentum after the collision = (total mass of the two cars) × (final velocity of the two cars) = (mass of the first car + mass of the second car) × (6.0 m/s)
According to the conservation of momentum principle:
Momentum before collision = Momentum after collision
(9500 kg) × (16 m/s) = (mass of the first car + mass of the second car) × (6.0 m/s)
From this equation, we can solve for the mass of the second car.
(mass of the first car + mass of the second car) = (9500 kg × 16 m/s) / (6.0 m/s)
mass of the second car = [(9500 kg × 16 m/s) / (6.0 m/s) ] - mass of the first car