# Chemistry

If 456 dm^3 of krypton at 101 kPa and 21 degrees C is compressed into a 27.0 dm^3 tank at the same temperature, what is the pressure of krypton in the tank?

V1= 456 dm^3
V2= 27.0 dm^3
P1= 101 kPa
P2= ?

P2= 101 kPa * 456 dm^3/ 27.0 dm^3

1705.78 kPa

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1. Is this right??

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2. Almost.
All of the digits are correct because the answer is a repeating number of 1705.7777777. However, you have only three (3) significant figures in the problem; therefore, you may have only 3 s.f. in the answer. So the answer should be rounded to 1.70 x 10^3. In rounding, and when the last number is a 5, I round to the nearest even number so the 0 stays and we drop the 5. Had the zero been a 1, we would have rounded up by making the 1 a 2 and droping the 5. And the scientific notation is necesssary in the answer because if we write it as 1700 we are showing four s.f.

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