Explain in words how you would prepare 250 ml of a 3.000 M solution of Ba(OH)2 starting from a two liter bottle of 12.000 M Ba(OH)2

To prepare a 250 ml of a 3.000 M solution of Ba(OH)2, you can follow these steps:

1. First, determine the volume of the original 12.000 M solution that is required to obtain the desired concentration. This can be done using the formula:
C1V1 = C2V2
Where:
C1 = initial concentration (12.000 M)
V1 = initial volume (unknown, to be determined)
C2 = final concentration (3.000 M)
V2 = final volume (250 ml or 0.250 L)

Substituting the values into the formula:

(12.000 M)(V1) = (3.000 M)(0.250 L)

Rearranging the equation and solving for V1:

V1 = (3.000 M)(0.250 L) / (12.000 M)

V1 = 0.0625 L or 62.5 ml

Therefore, you need 62.5 ml of the original 12.000 M solution.

2. Measure 62.5 ml of the 12.000 M Ba(OH)2 solution using a graduated cylinder or pipette.

3. Pour the measured 62.5 ml of the 12.000 M Ba(OH)2 solution into a container.

4. Add distilled water to the container to bring the total volume up to 250 ml.

5. Mix the solution thoroughly to ensure that the Ba(OH)2 is completely dissolved.

Now, you have your desired 250 ml of a 3.000 M Ba(OH)2 solution prepared from the original two-liter bottle of 12.000 M Ba(OH)2.