Water is added to 25 ml of a .911 M KNO3 solution until the volume of solution is exactly 500ml. What is the concentration of the final solution.
0.911 M x 25/500 = ??M OR
another way:
moles KNO3 = M x L = 0.025 x 0.911 = ??moles
Then M = moles KNO3/0.500 L.
You should obtain the same answer either way.
niobno'
To find the concentration of the final solution, we need to consider the amount of solute (KNO3) before and after the addition of water.
Before dilution:
- Volume of the KNO3 solution = 25 mL
- Concentration of the KNO3 solution = 0.911 M
After dilution:
- Volume of the final solution = 500 mL
Here's how to calculate the concentration of the final solution:
Step 1: Calculate the amount of KNO3 in the original solution.
Amount = Volume × Concentration
Amount = 25 mL × 0.911 M
Step 2: Calculate the amount of KNO3 in the final solution.
Since we're diluting the solution, the moles of KNO3 will remain the same.
Moles = Amount of solute (before dilution) = Amount of solute (after dilution)
Moles in the final solution = Moles in the original solution
Step 3: Calculate the concentration of the final solution.
Concentration = Moles / Volume
Concentration = Moles in the final solution / Volume of the final solution
Concentration = Moles in the final solution / 500 mL
Since the moles of KNO3 in the final solution are the same as in the original solution and we know the original volume, we can calculate the concentration of the final solution.
Please provide the amount of KNO3 in the original solution (from Step 1) to proceed with the calculation.