5 basketball teams are in a tournament and each team will play each other one time how many games will be played at the end?
5 teams: ABCDE
These teams will play each other:
AB AC AD AE
BC BD BE
CD CE
Sorry, I didn't finish and I accidentally hit enter.
AB AC AD AE
BC BD BE
CD CE
DE
(E has already played all of the teams.)
That's 10 games.
10
A team does not play against itself so the answer for 5 teams is:
4 + 3 +2 + 1 = 10games
To find the total number of games played at the end of the tournament, we need to determine how many games each team will play against the other teams.
In a round-robin tournament, each team plays against every other team exactly once.
We can calculate the number of games using the formula:
Number of games = nC2, where n is the number of teams and C2 represents the combination of choosing 2 teams to play against each other.
For this case, there are 5 teams, so we can substitute n = 5 into the formula:
Number of games = 5C2 = (5!)/(2!(5-2)!) = (5 x 4)/(2 x 1) = 10.
Therefore, at the end of the tournament, a total of 10 games will be played.