The decibel (dB) is defined as

dB= 10log (P2/P1), where P2 is the power of a particular signal. P1 is
the power of some reference signal. In the case of sounds, the reference signal is a sound level that
is just barely audible.How many dBs does a sound have if its power is 665,000 times that of the
reference sound? Round to the nearest tenth.
A) 134.1 dB
B) 58.2 dB
C) 25.3 dB
D) 10.0 dB
E) 0.0 dB

dB = 10log(665 000) = 58.23

To find the number of decibels (dB) for a sound with a power 665,000 times that of the reference sound, we can use the formula:

dB = 10log(P2/P1)

Here, P2 is the power of the particular sound, and P1 is the power of the reference sound.

Let's calculate it step by step:

1. Calculate the ratio of P2 to P1:
P2/P1 = 665,000

2. Take the logarithm (base 10) of the ratio:
log(P2/P1) = log(665,000)

3. Multiply the logarithm by 10:
10log(P2/P1) = 10 * log(665,000)

4. Finally, round the result to the nearest tenth:
Round(10 * log(665,000)) = 58.2 dB

Therefore, the sound has approximately 58.2 dB.

Answer:
B) 58.2 dB