A moving rod is 12.0 cm long and moves with a speed of 15.0 cm/s. If the magnetic field is 0.800 T, calculate (a) the emf developed, and (b) the electric field in the rod.
I got a)0.0132v and b).12v/m
The rod must move across the field lines.
EMF = B V L = (0.80)*(0.15 m/s)*(0.12 m) = 0.0144 V
E-field = V/L
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To solve these questions, we need to use the formula for the electromotive force (EMF) and the formula for the electric field in a moving rod.
(a) Calculating the EMF: The formula for the EMF developed in a moving rod is given by: EMF = B * L * V, where B is the magnetic field, L is the length of the rod, and V is the velocity of the rod.
Plugging in the values:
B = 0.800 T
L = 12.0 cm = 0.12 m
V = 15.0 cm/s = 0.15 m/s
EMF = 0.800 T * 0.12 m * 0.15 m/s
EMF = 0.0144 V
Therefore, the EMF developed in the rod is approximately 0.0144 V.
(b) Calculating the electric field: The formula for the electric field in a moving rod is given by: E = EMF / L, where EMF is the electromotive force and L is the length of the rod.
Plugging in the values:
EMF = 0.0144 V
L = 0.12 m
E = 0.0144 V / 0.12 m
E = 0.12 V/m
Therefore, the electric field in the rod is approximately 0.12 V/m.