chemistry

In a laboratory experiment, a 18.0 ml sample of NaCl solution is poured into an evaporating dish with a mass of 24.00 g. The combined mass of the evaporating dish and NaCl solution is 37.15g. After heating, the evaporating dish and dry NaCl have a combined mass of 26.50 g.
If water is added to 18.0 ml of the initial NaCl solution to give a final volume of 80.0 ml, what is the molarity of the dilute NaCl solution?

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asked by Allyse
  1. (Initial Molarity of NaCl)(Initial Volume of NaCl solution)=(?)(Final Volume of diluted solution)

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    posted by Crane
  2. e.d. = evaporation dish = 24.00
    mass e.d. + mass H2O + mass NaCl = 37.15g
    mass e.d. + mass NaCl = 26.50
    Subtract and mass H2O = 10.65
    Then 24.00 + 10.65 + mass NaCl = 37.15
    mass NaCl = 2.50 g
    moles NaCl = grams/molar mass
    M NaCl = moles NaCl/0.080 L = ??

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    posted by DrBob222

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