Larry leaves home at 1:01 and runs at a constant speed to the lamppost. He reaches the lamppost at 1:10, immediately turns, and runs to the tree. Larry arrives at the tree at 1:26. What is Larry's average velocity during his trip from home to the lamppost, if the lamppost is 346.0 m west of home, and the tree is 640.0 m east of home?
d = 2 * 346 + 640 = 1332 m,
t = 1:26 - 1:1 = 25 min,
v = d/t = 1332 m / 25 min = 53.3 m/min.
To find Larry's average velocity during his trip from home to the lamppost, we need to determine the total displacement and the total time he took for that portion of the trip.
Larry ran from home to the lamppost, which is 346.0 m west of home. The displacement is defined as the change in position, which in this case is the displacement between the lamppost and home.
Larry left home at 1:01 and reached the lamppost at 1:10, which means he took 9 minutes to reach the lamppost.
To calculate the average velocity, we divide the displacement by the time taken:
Average velocity = Displacement / Time
Average velocity = 346.0 m / 9 min
Now, we need to convert the time from minutes to seconds because the displacement is in meters:
Average velocity = 346.0 m / (9 min * 60 s/min)
Simplifying further:
Average velocity = 346.0 m / 540 s
Calculating the average velocity:
Average velocity = 0.6407 m/s (rounded to four decimal places)
Therefore, Larry's average velocity during his trip from home to the lamppost is approximately 0.6407 m/s.