Calcium carbonate CaCO3 reacts with stomach acid (HCl, hydrochloric acid) according to the following equation:
Tums, an antacid, contains CaCO3.
If Tums is added to 35.0 mL of 0.300 M HCl,how many grams of CO2 gas are produced?

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  1. Here is a sample problem I've posted on simply stoichiometry. Just follow the steps. moles in this case = M x L.

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  2. do i still need to find whether CaCO3 or HCl is the limiting reactant?

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  3. To be a limiting reagent type problem BOTH reactants must be given; i.e., you have 35.0 mL of 0.300 M HCl (one of the reactants) but you don't have the other one (only that it is TUMS but no mass is given nor a percent composition--I thing the assumption is that you have enough CCO3 to use all of the HCl).
    moles HCl = 0.035 x 0.300 = 0.0105

    Convert moles HCl to moles CO2 using the coefficients in the balanced equation.
    0.0105 moles HCl x (1 mole CO2/2 moles HCl) = 0.0105 x (1/2) = 0.00525
    Now convert moles CO2 to grams.
    g = moles x molar mass = ?? grams CO2.

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  4. thanks...

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  5. what volume of 0.150 m sotomach acid will caco3 nutralise ?

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