A bicyclist makes a trip that consists of three parts, each in the same direction (due north) along a straight road. During the first part, she rides for 22 minutes at an average speed of 6.80 m/s. During the second part, she rides for 36 minutes at an average speed of 5.40 m/s. Finally, during the third part, she rides for 8.0 minutes at an average speed of 11.1 m/s. How far has the bicyclist traveled during the entire trip?
Use X = V*t to compute the distance traveled during each part, and add the distances of the three parts.
During part 1, she travels
22 min*60 sec/min*6.80 m/s = 8976 m = 8.98 km
Now you finish the problem.
To find the distance traveled during the entire trip, we need to find the total distance traveled in each part of the trip and then add them together.
First, let's find the distance traveled in the first part of the trip. We know the average speed and the time traveled, so we can use the formula:
Distance = Speed x Time
In this case, the speed is 6.80 m/s and the time is 22 minutes. However, we need to convert the time to seconds, since the speed is given in meters per second. There are 60 seconds in a minute, so:
Time in seconds = 22 minutes x 60 seconds/minute = 1320 seconds
Now we can calculate the distance for the first part:
Distance 1 = 6.80 m/s x 1320 s = 8976 meters
Similarly, we can find the distance for the second part:
Time in seconds (second part) = 36 minutes x 60 seconds/minute = 2160 seconds
Distance 2 = 5.40 m/s x 2160 s = 11664 meters
And the distance for the third part:
Time in seconds (third part) = 8 minutes x 60 seconds/minute = 480 seconds
Distance 3 = 11.1 m/s x 480 s = 5328 meters
Now, we can find the total distance traveled by adding up the distances from each part:
Total distance = Distance 1 + Distance 2 + Distance 3
= 8976 meters + 11664 meters + 5328 meters
= 26016 meters
Therefore, the bicyclist has traveled a total distance of 26016 meters during the entire trip.