this is probablt really simple, but for some reason I can't find out how to do it...

solve for b;

2a/bc= 12

(show your work)

multiply both sides by b, then divide both sides by 12

Multiply both sides by b.

2a/c = 12b

Divide both sides by 12 and reduce.

a/6c = b

To solve for b in the equation 2a/bc = 12, you can follow these steps:

Step 1: Multiply both sides of the equation by bc to isolate b on the left side.
(2a/bc) * bc = 12 * bc

Step 2: Simplify the equation by canceling out bc on the left side and multiplying 12 with bc on the right side.
2a = 12bc

Step 3: Divide both sides of the equation by 12c to isolate b.
(2a) / (12c) = (12bc) / (12c)

Step 4: Simplify the equation further and cancel out 12 with 2 on the left side.
a / (6c) = b

Therefore, the solution for b is:
b = a / (6c)

So, to solve for b in the equation 2a/bc = 12, you divide a by 6c.