A baker uses sodium hydrogen carbonate as the leavening agent in a banana nut quickbread. the baking soda decomposes according to two possible reactions. 1. 2 NaHCO3 = Na2CO3+H2O+CO2
2. NaHCO3+H=H2O+CO2+Na. calculate the volume in mL of CO2 that forms at 180 degrees C and .975 atm per gram of NaHCO3 by each of the reaction processes. if you could show me an example thatd be great i just can't seem to get it to wokr out right
Use the first equation.
2NaHCO3 ==> Na2CO3 + H2O + CO2
The problem gives you 1.0 g NaHCO3 (or 1.0 g Na2CO3 for the second part). Convert 1.0 g NaHCO3 to moles. moles = grams/molar mass.
Using the coefficients in the balanced equation, convert moles NaHCO3 to mole CO2.
mols NaHCO3 x (1 mole CO2/2 mole NaHCO3) = moles NaHCO3 x (1/2) = xx
Use PV = nRT. You know P, n, R, and T. Solve for V which will be in L, then convert to mL.
To calculate the volume of CO2 that forms per gram of NaHCO3 using each reaction process, you need to use the ideal gas law equation:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature (in Kelvin)
First, let's calculate the number of moles of NaHCO3:
n = mass / molar mass
The molar mass of NaHCO3 is:
Na: 22.99 g/mol
H: 1.01 g/mol (x 1)
C: 12.01 g/mol
O: 16.00 g/mol (x 3)
So, the molar mass of NaHCO3 is:
22.99 + 1.01 + 12.01 + (16.00 x 3) = 84.00 g/mol
Now, we can calculate the number of moles (n) of NaHCO3.
n = mass of NaHCO3 / molar mass of NaHCO3
Next, let's calculate the volume of CO2 using each reaction process.
For reaction 1 (2 NaHCO3 = Na2CO3 + H2O + CO2):
n of CO2 = n of NaHCO3 (according to the stoichiometry)
For reaction 2 (NaHCO3 + H = H2O + CO2 + Na):
n of CO2 = n of NaHCO3 (according to the stoichiometry)
Now, substitute the values into the ideal gas law equation to calculate the volume of CO2.
V of CO2 = (n of CO2 * R * T) / P
Remember to convert the temperature to Kelvin by adding 273.15.
Let's calculate the volume of CO2 using reaction 1 at 180 degrees C and 0.975 atm per gram of NaHCO3.
Step 1: Calculate the number of moles of NaHCO3.
n = mass of NaHCO3 / molar mass of NaHCO3
Assuming you want to use 1 gram of NaHCO3, the number of moles would be:
n = 1 g / 84.00 g/mol = 0.0119 mol
Step 2: Calculate the volume of CO2.
V of CO2 = (n of CO2 * R * T) / P
Substituting the values:
V of CO2 = (0.0119 mol * 0.0821 L.atm/mol.K * (180 + 273.15) K) / 0.975 atm
Calculating the volume of CO2 will give you the answer in liters. If you want it in milliliters, simply multiply the result by 1000.
Repeat the same process for reaction 2 using the given conditions and mass of NaHCO3 to calculate the volume of CO2.
Note: Ensure that all units are consistent throughout the calculations and take care of significant figures.