A baker uses sodium hydrogen carbonate as the leavening agent in a banana nut quickbread. the baking soda decomposes according to two possible reactions. 1. 2 NaHCO3 = Na2CO3+H2O+CO2
2. NaHCO3+H=H2O+CO2+Na. calculate the volume in mL of CO2 that forms at 180 degrees C and .975 atm per gram of NaHCO3 by each of the reaction processes. if you could show me by steps that would really help i've tried using PV=nRT
You so the stoichiometry and calculate the moles CO2 present, then use PV = nRT to calculate volume.
To calculate the volume of CO2 formed per gram of NaHCO3, we need to use the ideal gas law equation, PV = nRT, where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
Step 1: Calculate the number of moles of NaHCO3
The molar mass of NaHCO3 is calculated as follows:
Na = 22.99 g/mol
H = 1.01 g/mol
C = 12.01 g/mol
O = 16.00 g/mol
So, the molar mass of NaHCO3 is 22.99 + 1.01 + (12.01 + 3 * 16.00) = 84.01 g/mol
Since we want to calculate the volume of CO2 per gram of NaHCO3, we need to convert the grams of NaHCO3 to moles. Let's assume we have 1 gram of NaHCO3.
Number of moles = mass (in grams) / molar mass
Number of moles = 1 g / 84.01 g/mol = 0.0119 mol
Step 2: Calculate the volume of CO2 using each reaction
For reaction 1: 2 NaHCO3 = Na2CO3 + H2O + CO2
According to the balanced equation, the molar ratio between NaHCO3 and CO2 is 2:1. This means that for each mole of NaHCO3, we will get 1 mole of CO2.
Therefore, for 0.0119 mol of NaHCO3:
Volume of CO2 (in L) = 0.0119 mol * (22.4 L/mol) = 0.2672 L = 267.2 mL (using 1 L = 1000 mL)
For reaction 2: NaHCO3 + H = H2O + CO2 + Na
Again, we have a 1:1 molar ratio between NaHCO3 and CO2.
Therefore, for 0.0119 mol of NaHCO3:
Volume of CO2 (in L) = 0.0119 mol * (22.4 L/mol) = 0.2672 L = 267.2 mL (using 1 L = 1000 mL)
So, regardless of which reaction occurs, the volume of CO2 formed per gram of NaHCO3 is approximately 267.2 mL.