Find an equation for the line with the given properties.
Containing the points (-5,4) and
(-2,-6)
Please help!
find the slope , call it m
write it as
y = mx + b
use one of the points to replace the x and y values, that way you can find b
put that back in, and you are done
let me know what you get
I got y=-10/3 x + b
Then I used (-5,4) so 4=-10/3(-5) + b
and I got y=-10/3x - 46/3. I am not sure if I multiplied and added the fractions correctly
I had b = -38/3
a trick is to use the point that was not used and sub it is, the other point does work for -38/3
To find the equation of a line, we can use the formula for the slope-intercept form, which is y = mx + b, where m represents the slope of the line, and b represents the y-intercept.
To get the equation of the line passing through the points (-5,4) and (-2,-6), we need to find the values of m and b.
Step 1: Calculate the slope (m)
The formula to find the slope (m) between two points (x1,y1) and (x2,y2) is:
m = (y2 - y1) / (x2 - x1)
Using the given points (-5,4) and (-2,-6), we can calculate the slope:
m = (-6 - 4) / (-2 - (-5))
m = (-10) / (3)
m = -10/3
Step 2: Find the y-intercept (b)
To find the y-intercept (b), we can substitute one of the given points into the equation.
Using the point (-5,4):
y = mx + b
4 = (-10/3)(-5) + b
4 = 50/3 + b
To isolate b, we can subtract 50/3 from both sides:
4 - 50/3 = b
(12 - 50)/3 = b
-38/3 = b
Step 3: Write the equation
Now that we have the values of m and b, we can write the equation:
y = (-10/3)x - 38/3
Thus, the equation of the line passing through the points (-5,4) and (-2,-6) is y = (-10/3)x - 38/3.