Given the function f(x)= x^2-3 / x+1, what point on the graph corresponds to x=-2?
I have no idea what to do. Am I suppose to plug in -2 into the equation?
Yes, just plug in -2 for x and solve y-coordinate (-2,__)!
f(-2)= [(-2)^2-3] / [(-2)+1]
I have no idea what to do. Am I suppose to plug in -2 into the equation?
f(-2)= [(-2)^2-3] / [(-2)+1]