How many moles of KMnO4 are present in 300 mL of a 4.90×10−2 M solution?
moles = M x L.
To find the number of moles of KMnO4 in the solution, first, we need to understand the relationship between molarity, volume, and moles.
Molarity (M) is defined as the number of moles of solute per liter of solution. Therefore, the formula for calculating moles of solute is:
Moles of solute = Molarity × Volume (in liters)
Given:
Molarity (M) = 4.90×10^(-2) M
Volume = 300 mL = 300 ÷ 1000 = 0.3 L (since 1 L = 1000 mL)
Now we can calculate the number of moles of KMnO4:
Moles of KMnO4 = Molarity × Volume
= (4.90×10^(-2) M) × (0.3 L)
= 0.147 moles
Therefore, there are 0.147 moles of KMnO4 present in 300 mL of a 4.90×10^(-2) M solution.