What is the specific heat (in cal) of fat with a degree change from 25 degrees Celsius to 35 degrees celsius? Density of fat = 0.94 g/cm^3
Use density to calculate mass, then
look in your problem for heat input, q.
q = mass fat x specific heat fat x delta T. Solve for specific heat fat.
The specific heat of toluene (C7H8), is 1.13 J/g•K. How many kJ of heat are necessary to raise the temperature of 61.0 g of toluene from 15.0 °C to 37.2 °C?
To find the specific heat of fat, we need to use the formula:
Q = m * c * ΔT
Here, Q represents the heat energy absorbed or released by the fat, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
To solve this problem, we need to know the mass (m) of the fat. Unfortunately, you haven't provided the mass of the substance. So, without knowing the mass, it is not possible to calculate the specific heat of fat in calories (cal) for the given temperature change.
If you have the mass of the fat, please provide it, and I will be able to help you calculate the specific heat.