Not sure how to do any of this. Please help!!!

A sample of the compound prepared in this experiment, weighing .1021g, is dissolved in HNO3 and diluted to a volume of 100mL. A 10mL aliquot of that solution is mixed iwth 10mL 6 M NH3. The [Cu(NH3)4 2+] in the resulting solution is 5.16x10^-3 M.

How many moles of Cu were in the original sample, which had been effectively diluted to a volume of 200mL?
How many grams of Cu were in the sample?
How many grams of Cl were in the sample? How many moles?
What is the formula of the Copper Chloride compound?

To find the number of moles of Cu in the original sample, we can use the concentration of [Cu(NH3)4 2+] in the resulting solution and the volume of the aliquot used.

1. First, calculate the number of moles of [Cu(NH3)4 2+] in the aliquot:
Moles of [Cu(NH3)4 2+] = Concentration of [Cu(NH3)4 2+] × Volume of aliquot
Moles of [Cu(NH3)4 2+] = 5.16x10^-3 M × 0.01 L
Moles of [Cu(NH3)4 2+] = 5.16x10^-5 moles

2. Since the aliquot was taken from a 100 mL solution, we can calculate the number of moles of [Cu(NH3)4 2+] in the original sample as follows:
Moles of [Cu(NH3)4 2+] in the original sample = Moles of [Cu(NH3)4 2+] × (Volume of original solution / Volume of aliquot)
Moles of [Cu(NH3)4 2+] in the original sample = 5.16x10^-5 moles × (100 mL / 10 mL)
Moles of [Cu(NH3)4 2+] in the original sample = 5.16x10^-4 moles

Therefore, there are 5.16x10^-4 moles of Cu in the original sample.

To find the grams of Cu in the sample, we need to use the molar mass of Cu.

3. The molar mass of Cu is 63.55 g/mol.
Grams of Cu in the sample = Moles of Cu × Molar mass of Cu
Grams of Cu in the sample = 5.16x10^-4 moles × 63.55 g/mol

You can calculate the exact value for the grams of Cu in the sample by performing the multiplication.

To find the grams and moles of Cl in the sample, we need to know the stoichiometry of the copper chloride compound. Unfortunately, this information is not provided in the question, so we cannot determine the exact values without additional information.

If you have the chemical equation for the reaction that produced the copper chloride compound, please provide it, and I can assist further in determining the grams and moles of Cl.