A man lifts a 2.7 kg stone vertically with his hand at a constant upward acceleration of 1.2 m/s2. What is the magnitude of the total force of the stone on the man's hand?
To find the magnitude of the total force of the stone on the man's hand, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a): F = m * a.
Given:
Mass of the stone (m) = 2.7 kg
Acceleration (a) = 1.2 m/s^2
To find the total force, we can substitute the given values into the formula:
F = 2.7 kg * 1.2 m/s^2
= 3.24 N
Therefore, the magnitude of the total force of the stone on the man's hand is 3.24 Newtons.