If you throw a ball straight upward at a speed of 11 m/s, How long will it take to return to its starting point?
what does hi mean ?
To calculate the time it takes for the ball to return to its starting point, we need to consider the vertical motion of the ball. In this case, we can use the equations of motion to find the time.
First, let's break down the given information:
Initial velocity (u) = 11 m/s (upward)
Final velocity (v) = 0 m/s (at the highest point, the ball momentarily stops before falling down)
Acceleration (a) = -9.8 m/s^2 (since the ball is subjected to gravity, acceleration is downward)
We can use the equation of motion: v = u + at
For the upward motion:
0 = 11 - 9.8t (substituting the given values)
Solving for t:
-9.8t = -11
t = -11 / -9.8
t ≈ 1.12 seconds
Since the time taken is for the upward motion, to get the total time for the ball to return to its starting point, we need to double this time.
Therefore, it will take approximately 2.24 seconds for the ball to return to its starting point.
hf=hi+Vi*t-4.9t^2 solve for t
hf=hi