Can you check this:
x^-3y^2/x^2y^-4
I think the answer is y^6/x^5
Thanks for explaining the other problem
correct, good job
Thank you so much for your help
To simplify the expression (x^-3y^2)/(x^2y^-4), we can use the laws of exponents.
Start by simplifying the numerator, x^-3y^2.
Recall that when you have a negative exponent, you can move the base to the denominator by changing the sign of the exponent. So x^-3 can be rewritten as 1/x^3.
Now let's simplify the denominator, x^2y^-4.
Similarly, y^-4 can be rewritten as 1/y^4.
Now, substitute the simplified forms back into the expression:
(1/x^3)(y^2)/(x^2)(1/y^4).
Next, let's simplify the expression further.
In the numerator, multiply y^2 by 1 to get y^2.
In the denominator, multiply 1/x^2 by (1/y^4) to get 1/(x^2y^4).
Now, we can cancel out common factors.
There is an x^2 in the denominator of the numerator and the denominator of the denominator, so these can be canceled out, leaving:
(y^2)/(xy^4).
Now, we can simplify further by dividing y^2 by y^4.
When you divide variables with the same base, you subtract the exponents. So y^2/y^4 can be simplified to y^(-4 + 2), which is y^(-2).
Therefore, the final simplified expression is y^-2/x.
Recall that a negative exponent indicates that the base is in the denominator. So y^-2 can be rewritten as 1/y^2.
Therefore, the simplified expression is 1/y^2x.