rry leaves home at 4:07 and runs at a constant speed to the lamppost. He reaches the lamppost at 4:11, immediately turns, and runs to the tree. Larry arrives at the tree at 4:22. What is Larry's average velocity during his entire trip, if the lamppost is 363.0 m west of home, and the tree is 699.0 m east of home?
avg velocity= distancetraveled/time
Do you have questions about how to compute this?
No..so is it 363+699+363 / 240s + 660s ?
To calculate Larry's average velocity during his entire trip, we need to find his total displacement and divide it by the total time taken.
First, let's calculate Larry's displacement from home to the lamppost. Given that the lamppost is 363.0 m west of home, the displacement to the lamppost is -363.0 m (negative because it is west).
Next, let's calculate Larry's displacement from the lamppost to the tree. Given that the tree is 699.0 m east of home, the displacement from the lamppost to the tree is +699.0 m (positive because it is east).
To find the total displacement, we need to add the displacements together: -363.0 m + 699.0 m = 336.0 m.
Now, let's calculate the total time taken. Larry started running at 4:07 and reached the lamppost at 4:11, so the time taken for the first leg of the trip is 4 minutes. Larry then turned and ran to the tree and arrived at 4:22, so the time taken for the second leg of the trip is 11 minutes.
To find the total time, we add the time taken for the first and second leg of the trip together: 4 minutes + 11 minutes = 15 minutes.
To calculate Larry's average velocity, we divide the total displacement by the total time:
Average velocity = Total displacement / Total time
Average velocity = 336.0 m / 15 minutes
Since velocity is defined as displacement over time, the units for average velocity would be meters per minute (m/min) in this case.